Fractional Precipitation Pogil Answer Key Best -

For PbCrO₄ (1:1 salt): [ [Pb^2+] = \frac2.8 \times 10^-130.050 = 5.6 \times 10^-12 M ]

| Salt | (K_sp) | |------|------------| | AgCl | (1.8 \times 10^-10) | | AgI | (8.5 \times 10^-17) | fractional precipitation pogil answer key best

Second precipitate (PbBr₂) begins at [Pb²⁺] = (2.64 \times 10^-3 M). At that [Pb²⁺], [CrO₄²⁻] remaining is: [ [CrO_4^2-] = \frac2.8 \times 10^-132.64 \times 10^-3 = 1.06 \times 10^-10 M ] For PbCrO₄ (1:1 salt): [ [Pb^2+] = \frac2

This calculation demonstrates why fractional precipitation works. The first ion (I⁻) is reduced to a negligible level before the second ion (Cl⁻) begins to react. Learning Objective 3: Common Mistakes and Misconceptions POGIL activities often include metacognitive questions. Here’s how a high-quality answer key addresses frequent errors. fractional precipitation pogil answer key best