[ [H^+] = \sqrt(0.100)(1.8 \times 10^-5) ] [ [H^+] = \sqrt1.8 \times 10^-6 ]

(to get 3H2 on left). [ 3H2 + 1.5O2 → 3H2O \quad ΔH = -857.4 , \textkJ ]

By: AP Curriculum Historians